std::remove_extent
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<metanoindex/>
<tbody> </tbody>| definiert in Header <type_traits>
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template< class T > struct remove_extent; |
(seit C++11) | |
Wenn
T ein Array von irgendeiner Art X ist, liefert das Element typedef type gleich X, sonst ist type T. Beachten Sie, dass, wenn T ein mehrdimensionales Array, nur die erste Dimension entfernt wird .Original:
If
T is an array of some type X, provides the member typedef type equal to X, otherwise type is T. Note that if T is a multidimensional array, only the first dimension is removed.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Mitglied Typen
Name
Original: Name The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Definition |
type
|
der Typ des Elements der
T Original: the type of the element of T The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Mögliche Implementierung
template<class T>
struct remove_extent { typedef T type; };
template<class T>
struct remove_extent<T[]> { typedef T type; };
template<class T, std::size_t N>
struct remove_extent<T[N]> { typedef T type;};
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Beispiel
#include <iostream>
#include <iterator>
#include <algorithm>
#include <type_traits>
template<class A>
typename std::enable_if< std::rank<A>::value == 1 >::type
print_1d(const A& a)
{
copy(a, a+std::extent<A>::value,
std::ostream_iterator<typename std::remove_extent<A>::type>(std::cout, " "));
std::cout << '\n';
}
int main()
{
int a[][3] = {{1,2,3},{4,5,6}};
// print_1d(a); // compile-time error
print_1d(a[1]);
}
Output:
4 5 6