std::is_constructible, std::is_trivially_constructible, std::is_nothrow_constructible
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<metanoindex/>
<tbody> </tbody>| definiert in Header <type_traits>
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template< class T, class... Args > struct is_constructible; |
(1) | (seit C++11) |
template< class T, class... Args > struct is_trivially_constructible; |
(2) | (seit C++11) |
template< class T, class... Args > struct is_nothrow_constructible; |
(3) | (seit C++11) |
1)
Wenn der Ausdruck
T obj(arg1, arg2, ... argN); ist wohlgeformt, da rvalue Verweise auf Args... als Argumente, bietet das Mitglied konstanten value gleich true. Für jede andere Art, value ist false .Original:
If the expression
T obj(arg1, arg2, ... argN); is well-formed, given rvalue references to Args... as arguments, provides the member constant value equal true. For any other type, value is false.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
2)
wie 1), aber der Konstruktor Ausdruck nicht nennen jede Operation, die nicht trivial ist .
Original:
same as 1), but the constructor expression does not call any operation that is not trivial.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
3)
Gleiche wie 1), aber der Konstruktor Expression noexcept .
Original:
same as 1), but the constructor expression is noexcept.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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Inherited from std::integral_constant
Member constants
value [statisch] |
true wenn T is constructible from Args... , false anders Original: true if T is constructible from Args... , false otherwise The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (public static Mitglied konstanten) |
Member functions
operator bool |
wandelt das Objekt bool, gibt value Original: converts the object to bool, returns value The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (öffentliche Elementfunktion) |
Member types
Type
Original: Type The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Definition |
value_type
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bool
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type
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std::integral_constant<bool, value>
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Beispiel
#include <iostream>
#include <type_traits>
class Foo {
int v1;
double v2;
public:
Foo(int n) : v1(n), v2() {}
Foo(int n, double f) noexcept : v1(n), v2(f) {}
};
int main() {
std::cout << "Foo is ...\n" << std::boolalpha
<< "\tTrivially-constructible from const Foo&? "
<< std::is_trivially_constructible<Foo, const Foo&>::value << '\n'
<< "\tTrivially-constructible from int? "
<< std::is_trivially_constructible<Foo, int>::value << '\n'
<< "\tConstructible from int? "
<< std::is_constructible<Foo, int>::value << '\n'
<< "\tNothrow-constructible from int? "
<< std::is_nothrow_constructible<Foo, int>::value << '\n'
<< "\tNothrow-constructible from int and double? "
<< std::is_nothrow_constructible<Foo, int, double>::value << '\n';
}
Output:
Foo is ...
Trivially-constructible from const Foo&? true
Trivially-constructible from int? false
Constructible from int? true
Nothrow-constructible from int? false
Nothrow-constructible from int and double? true
