std::search
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<metanoindex/>
<tbody> </tbody>| definiert in Header <algorithm>
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template< class ForwardIt1, class ForwardIt2 > ForwardIt1 search( ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last ); |
(1) | |
template< class ForwardIt1, class ForwardIt2, class BinaryPredicate > ForwardIt1 search( ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last, BinaryPredicate p ); |
(2) | |
Sucht nach dem ersten Teilfolge von Elementen
[s_first, s_last) im Bereich [first, last - (s_last - s_first)). Die erste Version verwendet operator== um die Elemente zu vergleichen, verwendet die zweite Version des gegebenen binären Prädikats p .Original:
Searches for the first subsequence of elements
[s_first, s_last) in the range [first, last - (s_last - s_first)). The first version uses operator== to compare the elements, the second version uses the given binary predicate p.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Parameter
| first, last | - | das Spektrum der Elemente zu untersuchen
Original: the range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| s_first, s_last | - | der Bereich der Elemente für
Original: the range of elements to search for The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| p | - | binary predicate which returns true if the elements should be treated as equal. The signature of the predicate function should be equivalent to the following:
The signature does not need to have |
| Type requirements | ||
-ForwardIt1, ForwardIt2 must meet the requirements of ForwardIterator.
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Rückgabewert
Iterator zum Anfang der ersten Teilfolge
[s_first, s_last) im Bereich [first, last - (s_last - s_first)). Wenn keine solche Teilfolge, ist last returned.Original:
Iterator to the beginning of first subsequence
[s_first, s_last) in the range [first, last - (s_last - s_first)). If no such subsequence is found, last is returned.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Wenn
[s_first, s_last) leer ist, wird first zurückgegeben. (seit C++11)Original:
If
[s_first, s_last) is empty, first is returned. (seit C++11)The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Komplexität
An den meisten
S*N Vergleiche, wo S = std::distance(s_first, s_last) und N = std::distance(first, last) .Original:
At most
S*N comparisons where S = std::distance(s_first, s_last) and N = std::distance(first, last).The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Mögliche Implementierung
| First version |
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template<class ForwardIt1, class ForwardIt2>
ForwardIt1 search(ForwardIt1 first, ForwardIt1 last,
ForwardIt2 s_first, ForwardIt2 s_last)
{
for (; ; ++first) {
ForwardIt1 it = first;
for (ForwardIt2 s_it = s_first; ; ++it, ++s_it) {
if (s_it == s_last) {
return first;
}
if (it == last) {
return last;
}
if (!(*it == *s_it)) {
break;
}
}
}
}
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| Second version |
template<class ForwardIt1, class ForwardIt2, class BinaryPredicate>
ForwardIt1 search(ForwardIt1 first, ForwardIt1 last,
ForwardIt2 s_first, ForwardIt2 s_last,
BinaryPredicate p)
{
for (; ; ++first) {
ForwardIt1 it = first;
for (ForwardIt2 s_it = s_first; ; ++it, ++s_it) {
if (s_it == s_last) {
return first;
}
if (it == last) {
return last;
}
if (!p(*it, *s_it)) {
break;
}
}
}
}
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Beispiel
| This section is incomplete |
