std::replace_copy, std::replace_copy_if
<metanoindex/>
<tbody> </tbody>| definiert in Header <algorithm>
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template< class InputIt, class OutputIt, class T > OutputIt replace_copy( InputIt first, InputIt last, OutputIt d_first, const T& old_value, const T& new_value ); |
(1) | |
template< class InputIt, class OutputIt, class UnaryPredicate, class T > OutputIt replace_copy_if( InputIt first, InputIt last, OutputIt d_first, UnaryPredicate p, const T& new_value ); |
(2) | |
Copies the all elements from the range [first, last) to another range beginning at d_first replacing all elements satisfying specific criteria with new_value. The first version replaces the elements that are equal to old_value, the second version replaces elements for which predicate p returns true. The source and destination ranges cannot overlap.
Parameter
| first, last | - | der Bereich der zu kopierenden Elemente
Original: the range of elements to copy The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| d_first | - | der Beginn des Zielbereichs
Original: the beginning of the destination range The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| old_value | - | der Wert der Elemente zu ersetzen
Original: the value of elements to replace The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| p | - | unary predicate which returns true wenn der Wert des Elements ersetzt werden sollte . Original: if the element value should be replaced The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. The signature of the predicate function should be equivalent to the following:
The signature does not need to have |
| new_value | - | der Wert als Ersatz verwenden
Original: the value to use as replacement The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| Type requirements | ||
-InputIt must meet the requirements of InputIterator.
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-OutputIt must meet the requirements of OutputIterator.
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Rückgabewert
You can help to correct and verify the translation. Click here for instructions.
Komplexität
last - first Anwendungen des Prädikats .last - first applications of the predicate.You can help to correct and verify the translation. Click here for instructions.
Mögliche Implementierung
| First version |
|---|
template<class InputIt, class OutputIt, class T>
OutputIt replace_copy(InputIt first, InputIt last, OutputIt d_first,
const T& old_value, const T& new_value)
{
for (; first != last; ++first) {
*d_first++ = (*first == old_value) ? new_value : *first;
}
return d_first;
}
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| Second version |
template<class InputIt, class OutputIt,
class UnaryPredicate, class T>
OutputIt replace_copy_if(InputIt first, InputIt last, OutputIt d_first,
UnaryPredicate p, const T& new_value)
{
for (; first != last; ++first) {
*d_first++ = (p( *first ) ? new_value : *first;
}
return d_first;
}
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Beispiel
The following copy prints a vector, replacing all values over 5 with 99 on the fly.
#include <algorithm>
#include <vector>
#include <iostream>
#include <iterator>
#include <functional>
int main()
{
std::vector<int> v{5, 7, 4, 2, 8, 6, 1, 9, 0, 3};
std::replace_copy_if(v.begin(), v.end(),
std::ostream_iterator<int>(std::cout, " "),
[](int n){return n > 5;}, 99);
std::cout << '\n';
}
Output:
5 99 4 2 99 99 1 99 0 3
