Bugfix: do not use default operation name types if not included in schema definition block by dondonz · Pull Request #3088 · graphql-java/graphql-java · GitHub
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2 changes: 1 addition & 1 deletion src/main/java/graphql/language/SDLExtensionDefinition.java
22 changes: 14 additions & 8 deletions src/main/java/graphql/schema/idl/SchemaGeneratorHelper.java
Original file line number Diff line number Diff line change
Expand Up @@ -909,10 +909,13 @@ void buildOperations(BuildContext buildCtx, GraphQLSchema.Builder schemaBuilder)

Optional<OperationTypeDefinition> mutationOperation = getOperationNamed("mutation", operationTypeDefs);
if (!mutationOperation.isPresent()) {
Optional<TypeDefinition> mutationTypeDef = typeRegistry.getType("Mutation");
if (mutationTypeDef.isPresent()) {
mutation = buildOutputType(buildCtx, TypeName.newTypeName().name(mutationTypeDef.get().getName()).build());
schemaBuilder.mutation(mutation);
if (!typeRegistry.schemaDefinition().isPresent()) {
// If no schema definition, then there is no schema keyword. Default to using type called Mutation
Optional<TypeDefinition> mutationTypeDef = typeRegistry.getType("Mutation");
if (mutationTypeDef.isPresent()) {
mutation = buildOutputType(buildCtx, TypeName.newTypeName().name(mutationTypeDef.get().getName()).build());
schemaBuilder.mutation(mutation);
}
}
} else {
mutation = buildOperation(buildCtx, mutationOperation.get());
Expand All @@ -921,10 +924,13 @@ void buildOperations(BuildContext buildCtx, GraphQLSchema.Builder schemaBuilder)

Optional<OperationTypeDefinition> subscriptionOperation = getOperationNamed("subscription", operationTypeDefs);
if (!subscriptionOperation.isPresent()) {
Optional<TypeDefinition> subscriptionTypeDef = typeRegistry.getType("Subscription");
if (subscriptionTypeDef.isPresent()) {
subscription = buildOutputType(buildCtx, TypeName.newTypeName().name(subscriptionTypeDef.get().getName()).build());
schemaBuilder.subscription(subscription);
if (!typeRegistry.schemaDefinition().isPresent()) {
// If no schema definition, then there is no schema keyword. Default to using type called Subscription
Optional<TypeDefinition> subscriptionTypeDef = typeRegistry.getType("Subscription");
if (subscriptionTypeDef.isPresent()) {
subscription = buildOutputType(buildCtx, TypeName.newTypeName().name(subscriptionTypeDef.get().getName()).build());
schemaBuilder.subscription(subscription);
}
}
} else {
subscription = buildOperation(buildCtx, subscriptionOperation.get());
Expand Down
119 changes: 119 additions & 0 deletions src/test/groovy/graphql/schema/idl/SchemaParserTest.groovy