std::mismatch
De cppreference.com
<metanoindex/>
<tbody> </tbody>| Definido no cabeçalho <algorithm>
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template< class InputIt1, class InputIt2 > std::pair<InputIt1,InputIt2> mismatch( InputIt1 first1, InputIt1 last1, InputIt2 first2 ); |
(1) | |
template< class InputIt1, class InputIt2, class BinaryPredicate > std::pair<InputIt1,InputIt2> mismatch( InputIt1 first1, InputIt1 last1, InputIt2 first2, BinaryPredicate p ); |
(2) | |
Retorna o par descasamento primeira de elementos de duas faixas: uma definida por
[first1, last1) e outra a partir de first2. A primeira versão da função usa operator== para comparar os elementos, a segunda versão usa o predicado binário dado p. Original:
Returns the first mismatching pair of elements from two ranges: one defined by
[first1, last1) and another starting at first2. The first version of the function uses operator== to compare the elements, the second version uses the given binary predicate p. The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Parâmetros
| first1, last1 | - | o primeiro intervalo de elementos
Original: the first range of the elements The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| first2 | - | o início da segunda gama de elementos
Original: the beginning of the second range of the elements The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| p | - | binary predicate which returns true if the elements should be treated as equal. The signature of the predicate function should be equivalent to the following:
The signature does not need to have |
| Type requirements | ||
-InputIt1 must meet the requirements of InputIterator.
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-InputIt2 must meet the requirements of InputIterator.
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-OutputIt must meet the requirements of OutputIterator.
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Valor de retorno
std::pair com iteradores para os dois primeiros elementos não-equivalentes, ou, se não houver diferentes elementos encontrados, par com
last1 eo iterator correspondente a partir da segunda faixa.Original:
std::pair with iterators to the first two non-equivalent elements, or, if no different elements found, pair with
last1 and the corresponding iterator from the second range.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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Complexidade
No máximo
last1 - first1 aplicações do predicadoOriginal:
At most
last1 - first1 applications of the predicateThe text has been machine-translated via Google Translate.
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You can help to correct and verify the translation. Click here for instructions.
Possível implementação
| First version |
|---|
template<class InputIt1, class InputIt2>
std::pair<InputIt1, InputIt2>
mismatch(InputIt1 first1, InputIt1 last1, InputIt2 first2)
{
while (first1 != last1 && *first1 == *first2) {
++first1, ++first2;
}
return std::make_pair(first1, first2);
}
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| Second version |
template<class InputIt1, class InputIt2, class BinaryPredicate>
std::pair<InputIt1, InputIt2>
mismatch(InputIt1 first1, InputIt1 last1, InputIt2 first2, BinaryPredicate p)
{
while (first1 != last1 && p(*first1, *first2)) {
++first1, ++first2;
}
return std::make_pair(first1, first2);
}
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Exemplo
Este programa determina a substring mais longa do que é, simultaneamente, encontrado no início da string e no final do mesmo, em ordem inversa (possivelmente sobrepostas)
Original:
This program determines the the longest substring that is simultaneously found at the very beginning of the given string and at the very end of it, in reverse order (possibly overlapping)
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
#include <iostream>
#include <string>
#include <algorithm>
std::string mirror_ends(const std::string& in)
{
return std::string(in.begin(),
std::mismatch(in.begin(), in.end(), in.rbegin()).first);
}
int main()
{
std::cout << mirror_ends("abXYZba") << '\n'
<< mirror_ends("abca") << '\n'
<< mirror_ends("aba") << '\n';
}
Saída:
ab
a
aba