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Yet another PyTorch implementation of Stable Diffusion (probably easy to read)
Python 594 63
# 파희
아희로 구현한 원주율 계산기입니다.
Spigot 알고리즘을 이용하여 원주율의 (정수부 포함) 15000자리를 계산하여 출력합니다.
`reference.c`를 바탕으로 만들었습니다.
encrypt=async(P,Q,K,N)=>{I=-64;do{T=U=Uint32Array,J=0;O=await(A=async(...V)=>W(await(new Blob(V)).arrayBuffer()))("expand 32-byte k",K,(W=x=>new U(x))([I/64+1]),N),R=O.slice(),(D=b=>(S=[7,8,12,L=16],J<80&&(B=(W,Z,Y,X)=>(s=S.pop())&&(w=O[W]^=O[X]+=O[Y],O[W]<<=s,O[W]|=w>>>-s,B(Y,X,W,Z)))((M=i=>i*4+((J/4&1&&i)+J)%4)(3),M(2),M(1),J++%4)+D()))();for(i=L;i;O[--i]+=R[i]);U=Uint8Array;O=await A(O);P=I?P:W(P);Y=I<0?O:Y;for(i=0;i<64;i++)P[I++]^=O[i]}while(P[I]+1);r=(F=(a,i,j)=>(j??=L)?BigInt(a[i])+F(a,i+1,--j)*(Z=256n):0n)(Y,0)&0xffffffc0ffffffc0ffffffc0fffffffn;a=0n;p=P[l='length'],q=Q[l],k=(1<<30)*4,Q=await A(Q,(X=x=>W(x%L&&L-x%L))(q),P,X(p),new T([q,q/k,p,p/k]));for(I=0;Q[I]+1;I+=L)a=(a+F(Q,I)+(1n<<128n))*r%((1n<<130n)-5n);a+=F(Y,L);return[P,W(L).map(t=>(r=a%Z,a/=Z,`${r}`))]}
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