Add a naive recursive implementation of 0-1 Knapsack Problem by tbsschroeder · Pull Request #2743 · TheAlgorithms/Python · GitHub
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32 changes: 32 additions & 0 deletions knapsack/README.md
Empty file added knapsack/__init__.py
Empty file.
47 changes: 47 additions & 0 deletions knapsack/knapsack.py
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from typing import List

""" A naive recursive implementation of 0-1 Knapsack Problem
https://en.wikipedia.org/wiki/Knapsack_problem
"""


def knapsack(capacity: int, weights: List[int], values: List[int], counter: int) -> int:
"""
Returns the maximum value that can be put in a knapsack of a capacity cap,
whereby each weight w has a specific value val.

>>> cap = 50
>>> val = [60, 100, 120]
>>> w = [10, 20, 30]
>>> c = len(val)
>>> knapsack(cap, w, val, c)
220

The result is 220 cause the values of 100 and 120 got the weight of 50
which is the limit of the capacity.
"""

# Base Case
if counter == 0 or capacity == 0:
return 0

# If weight of the nth item is more than Knapsack of capacity,
# then this item cannot be included in the optimal solution,
# else return the maximum of two cases:
# (1) nth item included
# (2) not included
if weights[counter - 1] > capacity:
return knapsack(capacity, weights, values, counter - 1)
else:
left_capacity = capacity - weights[counter - 1]
new_value_included = values[counter - 1] + knapsack(
left_capacity, weights, values, counter - 1
)
without_new_value = knapsack(capacity, weights, values, counter - 1)
return max(new_value_included, without_new_value)


if __name__ == "__main__":
import doctest

doctest.testmod()
52 changes: 52 additions & 0 deletions knapsack/test_knapsack.py