std::ranges::join_view<V>::begin
From cppreference.com
constexpr auto begin();
|
(1) | (since C++20) |
constexpr auto begin() const
requires ranges::input_range<const V> &&
std::is_reference_v<ranges::range_reference_t<const V>>;
|
(2) | (since C++20) |
Returns an iterator to the first element of the join_view. Given base_ is the underlying view,
1) Equivalent to
return /*iterator*/<true>{*this, ranges::begin(base_)};if/*simple-view*/<V>is satisfied andranges::range_reference_t<V>is reference type. Otherwise,return /*iterator*/<false>{*this, ranges::begin(base_)};.
2) Equivalent to
return /*iterator*/<true>{*this, ranges::begin(base_)};.Parameters
(none)
Return value
Iterator to the first element.
Notes
When ranges::range_reference_t<V> is not a reference type, that is, deferencing an iterator of V returns a prvalue temporary, the join_view is only an input_range, in which case only single-pass iteration is supported, and repeated calls to begin() may not give meaningful results.
Example
| This section is incomplete Reason: no example |
