Escape sequences
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Escape-Sequenzen werden verwendet, um bestimmte Sonderzeichen in String-Literalen zu definieren.
Die folgenden Escape-Sequenzen stehen zur Verfügung:
Notes
Die new-line Zeichen
\n hat eine besondere Bedeutung, wenn im Text-Modus I / O verwendet wird, wird es dem OS-spezifische newline Byte oder Byte-Sequenz umgewandelt .Original:
The new-line character
\n has special meaning when used in text mode I/O, it is converted to the OS-specific newline byte or byte sequence.The text has been machine-translated via Google Translate.
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Octal Escape-Sequenzen haben eine Frist von drei Oktalziffern, sondern enden an der ersten Zeichen, das nicht ein gültiger Oktalziffer ggf. auch früher .
Original:
Octal escape sequences have a limit of three octal digits, but terminate at the first character that is not a valid octal digit if encountered sooner.
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Hexadezimale Escape-Sequenzen haben keine Längenbegrenzung und enden mit dem ersten Zeichen, die keine gültige Hexadezimalzahl. Wenn der Wert von einem einzigen hexadezimale Escape-Sequenz dargestellt nicht passt den Bereich der Werte von der Charakter-Typ in dieser Zeichenfolge vertreten Literal (
char, char16_t, char32_t oder wchar_t), ist das Ergebnis nicht näher .Original:
Hexadecimal escape sequences have no length limit and terminate at the first character that is not a valid hexadecimal digit. If the value represented by a single hexadecimal escape sequence does not fit the range of values represented by the character type used in this string literal (
char, char16_t, char32_t, or wchar_t), the result is unspecified.The text has been machine-translated via Google Translate.
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Eine universelle Charakter-Namen in einem engen String-Literal kann mehr als ein char aufgrund zuordnen Kodierung multibyte .
Original:
A universal character name in a narrow string literal may map to more than one char due to multibyte encoding.
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Das Fragezeichen Escape-Sequenz
\? wird verwendet, um trigraphs aus im Inneren Zeichenfolgenliterale interpretiert wird: ein String, wie "??/" als "\" kompiliert, aber wenn das zweite Fragezeichen entgangen, wie in "?\?/", wird es "??/"Original:
The question mark escape sequence
\? is used to prevent trigraphs from being interpreted inside string literals: a string such as "??/" is compiled as "\", but if the second question mark is escaped, as in "?\?/", it becomes "??/"The text has been machine-translated via Google Translate.
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Beispiel
#include <iostream>
int main()
{
std::printf("This\nis\na\ntest\n\nShe said, \"How are you?\"\n");
}
Output:
This
is
a
test
She said, "How are you?"