std::numeric_limits<T>::min_exponent10
From cppreference.com
static const int min_exponent10;
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(until C++11) | |
static constexpr int min_exponent10;
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(since C++11) | |
The value of std::numeric_limits<T>::min_exponent10 is the lowest negative number n such that 10n
is a valid normalized value of the floating-point type T.
Standard specializations
T
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value of std::numeric_limits<T>::min_exponent10
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/* non-specialized */
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0
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bool
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0
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char
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0
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signed char
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0
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unsigned char
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0
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wchar_t
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0
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char8_t (since C++20)
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0
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char16_t (since C++11)
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0
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char32_t (since C++11)
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0
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short
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0
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unsigned short
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0
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int
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0
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unsigned int
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0
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long
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0
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unsigned long
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0
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long long (since C++11)
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0
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unsigned long long (since C++11)
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0
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float
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FLT_MIN_10_EXP |
double
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DBL_MIN_10_EXP |
long double
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LDBL_MIN_10_EXP |
Example
Demonstrates the relationships of min_exponent, min_exponent10, min(), and radix for the type float:
Run this code
#include <iostream>
#include <limits>
int main()
{
std::cout << "min() = " << std::numeric_limits<float>::min() << '\n'
<< "min_exponent10 = " << std::numeric_limits<float>::min_exponent10 << '\n'
<< std::hexfloat << '\n'
<< "min() = " << std::numeric_limits<float>::min() << '\n'
<< "min_exponent = " << std::numeric_limits<float>::min_exponent << '\n';
}
Output:
min() = 1.17549e-38
min_exponent10 = -37
min() = 0x1p-126
min_exponent = -125