std::move_iterator<Iter>::operator*,->
From cppreference.com
reference operator*() const;
|
(1) | (since C++11) (constexpr since C++17) |
pointer operator->() const;
|
(2) | (since C++11) (constexpr since C++17) (deprecated in C++20) |
Returns an rvalue reference or pointer to the current element.
Return value
2)
currentNotes
operator-> is deprecated because deferencing its result may yield an lvalue. This may lead to unintended behavior.
Example
Run this code
#include <iomanip>
#include <iostream>
#include <iterator>
#include <string>
#include <vector>
void print(auto rem, const auto& v)
{
for (std::cout << rem; const auto& e : v)
std::cout << std::quoted(e) << ' ';
std::cout << '\n';
}
int main()
{
std::vector<std::string> p{"alpha", "beta", "gamma", "delta"}, q;
print("1) p: ", p);
for (std::move_iterator it{p.begin()}, end{p.end()}; it != end; ++it)
{
it->push_back('!'); // calls -> string::push_back(char)
q.emplace_back(*it); // *it <- overload (1)
}
print("2) p: ", p);
print("3) q: ", q);
std::vector v{1, 2, 3};
std::move_iterator it{v.begin()};
// *it = 13; // error: using rvalue as lvalue
}
Possible output:
1) p: "alpha" "beta" "gamma" "delta"
2) p: "" "" "" ""
3) q: "alpha!" "beta!" "gamma!" "delta!"
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
| DR | Applied to | Behavior as published | Correct behavior |
|---|---|---|---|
| LWG 2106 | C++11 | operator* would return a dangling reference ifdereferencing the underlying iterator yields a prvalue |
returns by value in this case |
