std::chrono::operator+, std::chrono::operator- (std::chrono::year_month_weekday)
From cppreference.com
1,2) Adds
dm.count() months to the date represented by ymwd. The result has the same year() and month() as std::chrono::year_month(ymwd.year(), ymwd.month()) + dm and the same weekday() and index() as ymwd.3,4) Adds
dy.count() years to the date represented by ymwd. The result is equivalent to std::chrono::year_month_weekday(ymwd.year() + dy, ymwd.month(), ymwd.weekday_indexed()).5) Subtracts
dm.count() months from the date represented by ymwd. Equivalent to ymwd + -dm.6) Subtracts
dy.count() years from the date represented by ymwd. Equivalent to ymwd + -dy.For durations that are convertible to both std::chrono::years and std::chrono::months, the years overloads (3,4,6) are preferred if the call would otherwise be ambiguous.
Notes
Even if ymwd.ok() is true, the resulting year_month_weekday may not represent a valid date if ymwd.index() is 5.
Example
Run this code
#include <cassert>
#include <chrono>
#include <iostream>
int main()
{
auto ymwdi{1/std::chrono::Wednesday[1]/2021};
std::cout << ymwdi << '\n';
ymwdi = std::chrono::years(5) + ymwdi;
// First Wednesday in January, 2026
std::cout << ymwdi << '\n';
assert(static_cast<std::chrono::year_month_day>(ymwdi) ==
std::chrono::January/7/2026);
ymwdi = ymwdi - std::chrono::months(6);
// First Wednesday in July, 2025
std::cout << ymwdi << '\n';
assert(static_cast<std::chrono::year_month_day>(ymwdi) ==
std::chrono::July/2/2025);
}
Output:
2021/Jan/Wed[1]
2026/Jan/Wed[1]
2025/Jul/Wed[1]
