ispunct
From cppreference.com
| Defined in header <ctype.h>
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int ispunct( int ch );
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Checks if the given character is a punctuation character in the current C locale. The default C locale classifies the characters !"#$%&'()*+,-./:;<=>?@[\]^_`{|}~ as punctuation.
The behavior is undefined if the value of ch is not representable as unsigned char and is not equal to EOF.
Parameters
| ch | - | character to classify |
Return value
Non-zero value if the character is a punctuation character, zero otherwise.
Example
Run this code
#include <ctype.h>
#include <locale.h>
#include <stdio.h>
int main(void)
{
unsigned char c = '\xd7'; // the character × (multiplication sign) in ISO-8859-1
printf("In the default C locale, \\xd7 is %spunctuation\n",
ispunct(c) ? "" : "not " );
setlocale(LC_ALL, "en_GB.iso88591");
printf("In ISO-8859-1 locale, \\xd7 is %spunctuation\n",
ispunct(c) ? "" : "not " );
}
Possible output:
In the default C locale, \xd7 is not punctuation
In ISO-8859-1 locale, \xd7 is punctuation
References
- C23 standard (ISO/IEC 9899:2024):
- 7.4.1.9 The ispunct function (p: TBD)
- C17 standard (ISO/IEC 9899:2018):
- 7.4.1.9 The ispunct function (p: 146)
- C11 standard (ISO/IEC 9899:2011):
- 7.4.1.9 The ispunct function (p: 202)
- C99 standard (ISO/IEC 9899:1999):
- 7.4.1.9 The ispunct function (p: 183)
- C89/C90 standard (ISO/IEC 9899:1990):
- 4.3.1.8 The ispunct function
See also
(C95) |
checks if a wide character is a punctuation character (function) |
C++ documentation for ispunct
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