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import java.util.Arrays;

import java.util.Stack;

/**

* Given an absolute path for a file (Unix-style), simplify it.

* <p>

* For example,

* path = "/home/", => "/home"

* path = "/a/./b/../../c/", => "/c"

* click to show corner cases.

* <p>

* Corner Cases:

* Did you consider the case where path = "/../"?

* In this case, you should return "/".

* Another corner case is the path might contain multiple slashes '/' together, such as "/home//foo/".

* In this case, you should ignore redundant slashes and return "/home/foo".

* <p>

* Created by drfish on 6/7/2017.

*/

public class _071SimplifyPath {

public String simplifyPath(String path) {

if (path == null) {

return "";

}

String[] parts = path.split("/");

Stack<String> stack = new Stack<>();

for (String part : parts) {

switch (part) {

case ".":

break;

case "":

break;

case "..":

if (!stack.isEmpty()) {

stack.pop();

}

break;

default:

stack.push(part);

}

}

String result = "";

for (String s : stack) {

result += "/" + s;

}

return result.length() == 0 ? "/" : result;

}

public static void main(String[] args) {

_071SimplifyPath solution = new _071SimplifyPath();

assert "/home".equals(solution.simplifyPath("/home/"));

assert "/c".equals(solution.simplifyPath("/a/./b/../../c/"));

assert "/".equals(solution.simplifyPath("/home/../../.."));

}

}