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# flake8: noqa

"""The following implementation assumes that the activities

are already sorted according to their finish time"""

"""Prints a maximum set of activities that can be done by a

single person, one at a time"""

# n --> Total number of activities

# start[]--> An array that contains start time of all activities

# finish[] --> An array that contains finish time of all activities

def printMaxActivities(start, finish):

"""

>>> start = [1, 3, 0, 5, 8, 5]

>>> finish = [2, 4, 6, 7, 9, 9]

>>> printMaxActivities(start, finish)

The following activities are selected:

0 1 3 4

"""

n = len(finish)

print("The following activities are selected:")

# The first activity is always selected

i = 0

print(i, end=" ")

# Consider rest of the activities

for j in range(n):

# If this activity has start time greater than

# or equal to the finish time of previously

# selected activity, then select it

if start[j] >= finish[i]:

print(j, end=" ")

i = j

# Driver program to test above function

start = [1, 3, 0, 5, 8, 5]

finish = [2, 4, 6, 7, 9, 9]

printMaxActivities(start, finish)

"""

The following activities are selected:

0 1 3 4

"""

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