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TheAlgorithms-Python/dynamic_programming/fizz_buzz.py at master · shepardo/TheAlgorithms-Python · GitHub

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# https://en.wikipedia.org/wiki/Fizz_buzz#Programming

def fizz_buzz(number: int, iterations: int) -> str:

"""

Plays FizzBuzz.

Prints Fizz if number is a multiple of 3.

Prints Buzz if its a multiple of 5.

Prints FizzBuzz if its a multiple of both 3 and 5 or 15.

Else Prints The Number Itself.

>>> fizz_buzz(1,7)

'1 2 Fizz 4 Buzz Fizz 7 '

>>> fizz_buzz(1,0)

Traceback (most recent call last):

...

ValueError: Iterations must be done more than 0 times to play FizzBuzz

>>> fizz_buzz(-5,5)

Traceback (most recent call last):

...

ValueError: starting number must be

and integer and be more than 0

>>> fizz_buzz(10,-5)

Traceback (most recent call last):

...

ValueError: Iterations must be done more than 0 times to play FizzBuzz

>>> fizz_buzz(1.5,5)

Traceback (most recent call last):

...

ValueError: starting number must be

and integer and be more than 0

>>> fizz_buzz(1,5.5)

Traceback (most recent call last):

...

ValueError: iterations must be defined as integers

"""

if not isinstance(iterations, int):

raise ValueError("iterations must be defined as integers")

if not isinstance(number, int) or not number >= 1:

raise ValueError(

"""starting number must be

and integer and be more than 0"""

)

if not iterations >= 1:

raise ValueError("Iterations must be done more than 0 times to play FizzBuzz")

out = ""

while number <= iterations:

if number % 3 == 0:

out += "Fizz"

if number % 5 == 0:

out += "Buzz"

if 0 not in (number % 3, number % 5):

out += str(number)

# print(out)

number += 1

out += " "

return out

if __name__ == "__main__":

import doctest

doctest.testmod()