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// Source : https://oj.leetcode.com/problems/reverse-integer/

// Author : Hao Chen

// Date : 2014-06-18

/**********************************************************************************

*

* Reverse digits of an integer.

*

* Example1: x = 123, return 321

* Example2: x = -123, return -321

*

*

* Have you thought about this?

*

* Here are some good questions to ask before coding. Bonus points for you if you have already thought through this!

*

* > If the integer's last digit is 0, what should the output be? ie, cases such as 10, 100.

*

* > Did you notice that the reversed integer might overflow? Assume the input is a 32-bit integer,

* then the reverse of 1000000003 overflows. How should you handle such cases?

*

* > Throw an exception? Good, but what if throwing an exception is not an option?

* You would then have to re-design the function (ie, add an extra parameter).

*

*

**********************************************************************************/

#include <stdio.h>

int reverse(int x) {

int y=0;

int n;

while( x != 0){

n = x%10;

y = y*10 + n;

x /= 10;

}

return y;

}

int main()

{

printf("%d, %d\n", 123, reverse(123));

printf("%d, %d\n", -123, reverse(-123));

printf("%d, %d\n", 100, reverse(100));

printf("%d, %d\n", 1002, reverse(1002));

//overflow

printf("%d, %d\n", 1000000003 , reverse(1000000003 ));

printf("%d, %d\n", -2147447412 , reverse(-2147447412 ));

printf("%d\n", -2147447412 == reverse(-2147447412 ));

return 0;

}