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/* A Dynamic Programming solution for Rod cutting problem

Returns the best obtainable price for a rod of

length n and price[] as prices of different pieces */

public class RodCutting

{

private static int cutRod(int price[],int n)

{

int val[] = new int[n+1];

val[0] = 0;

for (int i = 1; i<=n; i++)

{

int max_val = Integer.MIN_VALUE;

for (int j = 0; j < i; j++)

max_val = Math.max(max_val,price[j] + val[i-j-1]);

val[i] = max_val;

}

return val[n];

}

//main function to test

public static void main(String args[])

{

int arr[] = new int[] {2, 5, 13, 19, 20};

int size = arr.length;

System.out.println("Maximum Obtainable Value is " +

cutRod(arr, size));

}

}