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EditDistance.java

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/**

* Given two words word1 and word2, find the minimum number of steps required to convert word1 to

* word2. (each operation is counted as 1 step.)

*

* <p>You have the following 3 operations permitted on a word:

*

* <p>a) Insert a character b) Delete a character c) Replace a character

*/

public class EditDistance {

public int minDistance(String word1, String word2) {

if (word1.length() == 0 || word2.length() == 0)

return word1.length() == 0 ? word2.length() : word1.length();

int[][] arr = new int[word2.length() + 1][word1.length() + 1];

for (int i = 0; i <= word1.length(); i++) {

arr[0][i] = i;

}

for (int j = 0; j <= word2.length(); j++) {

arr[j][0] = j;

}

for (int i = 0; i < word1.length(); i++) {

for (int j = 0; j < word2.length(); j++) {

if (word1.charAt(i) == word2.charAt(j)) {

arr[j + 1][i + 1] = arr[j][i];

} else {

int dis = Math.min(arr[j][i + 1], arr[j + 1][i]);

arr[j + 1][i + 1] = Math.min(arr[j][i], dis) + 1;

}

}

}

return arr[word2.length()][word1.length()];

}

public static void main(String[] args) {

System.out.println(new EditDistance().minDistance("ab", "bc"));

}

}