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import rx.Observable;

import java.util.List;

/**

*

* Create two Observables

* Merge them

* Reduce the two results into one

* Map the result to the format you want

* Print it to screen using method subscribe()

*

* Created by matie on 28/04/15.

*/

public class example7 {

private static Integer[] firstList = {1,3,5};

private static Integer[] secondList = {2,4,6};

private static Observable<Integer> firstObservable = Observable.from(firstList);

private static Observable<Integer> secondObservable = Observable.from(secondList);

public static void main(String[] args){

//reduce() will sum first item with the second, combined with the third, and so on

Observable.merge(firstObservable, secondObservable)

.reduce((first, second) -> first + second)

.map(num -> "Sum of items: " + num)

.subscribe(message -> System.out.println(message));

//reduce() with an initialValue will sum [initial + (first) + (second) + (third)...]

int initialValue = 10;

Observable.merge(firstObservable, secondObservable)

.reduce(initialValue, (first, second) -> first + second)

.map(num -> "Sum with initial value of 10: " + num)

.subscribe(message -> System.out.println(message));

//reduce() with an initialValue will sum [initial + (initial+first) + (initial+second) + (initial+third)...]

Observable.merge(firstObservable, secondObservable)

.reduce(initialValue, (first, second) -> initialValue + first + second)

.map(num -> "Sum with initial value of 10 in function: " + num)

.subscribe(message -> System.out.println(message));

//observe how the two observables become one

Observable.merge(firstObservable, secondObservable)

.map(num -> "Single item: " + num)

.subscribe(message -> System.out.println(message));

}

}