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codeql
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ql
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CWE-730
/
PolynomialReDoS.qhelp
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codeql
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ql
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CWE-730
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PolynomialReDoS.qhelp
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<!
DOCTYPE
qhelp
PUBLIC
"-//Semmle//qhelp//EN"
"qhelp.dtd">
<
qhelp
>
<
include
src
=
"
ReDoSIntroduction.inc.qhelp
"
/>
<
example
>
<
p
>
Consider this use of a regular expression, which removes
all leading and trailing whitespace in a string:
</
p
>
<
sample
language
=
"
python
"
>
re.sub(r"^\s+|\s+$", "", text) # BAD</
sample
>
<
p
>
The sub-expression <
code
>"\s+$"</
code
> will match the
whitespace characters in <
code
>text</
code
> from left to right, but it
can start matching anywhere within a whitespace sequence. This is
problematic for strings that do <
strong
>not</
strong
> end with a whitespace
character. Such a string will force the regular expression engine to
process each whitespace sequence once per whitespace character in the
sequence.
</
p
>
<
p
>
This ultimately means that the time cost of trimming a
string is quadratic in the length of the string. So a string like
<
code
>"a b"</
code
> will take milliseconds to process, but a similar
string with a million spaces instead of just one will take several
minutes.
</
p
>
<
p
>
Avoid this problem by rewriting the regular expression to
not contain the ambiguity about when to start matching whitespace
sequences. For instance, by using a negative look-behind
(<
code
>^\s+|(?
<
!\s)\s+$</
code
>), or just by using the built-in strip
method (<
code
>text.strip()</
code
>).
</
p
>
<
p
>
Note that the sub-expression <
code
>"^\s+"</
code
> is
<
strong
>not</
strong
> problematic as the <
code
>^</
code
> anchor restricts
when that sub-expression can start matching, and as the regular
expression engine matches from left to right.
</
p
>
</
example
>
<
example
>
<
p
>
As a similar, but slightly subtler problem, consider the
regular expression that matches lines with numbers, possibly written
using scientific notation:
</
p
>
<
sample
language
=
"
python
"
>
^0\.\d+E?\d+$ # BAD</
sample
>
<
p
>
The problem with this regular expression is in the
sub-expression <
code
>\d+E?\d+</
code
> because the second
<
code
>\d+</
code
> can start matching digits anywhere after the first
match of the first <
code
>\d+</
code
> if there is no <
code
>E</
code
> in
the input string.
</
p
>
<
p
>
This is problematic for strings that do <
strong
>not</
strong
>
end with a digit. Such a string will force the regular expression
engine to process each digit sequence once per digit in the sequence,
again leading to a quadratic time complexity.
</
p
>
<
p
>
To make the processing faster, the regular expression
should be rewritten such that the two <
code
>\d+</
code
> sub-expressions
do not have overlapping matches: <
code
>^0\.\d+(E\d+)?$</
code
>.
</
p
>
</
example
>
<
example
>
<
p
>
Sometimes it is unclear how a regular expression can be rewritten to
avoid the problem. In such cases, it often suffices to limit the
length of the input string. For instance, the following
regular expression is used to match numbers, and on some non-number
inputs it can have quadratic time complexity:
</
p
>
<
sample
language
=
"
python
"
>
match = re.search(r'^(\+|-)?(\d+|(\d*\.\d*))?(E|e)?([-+])?(\d+)?$', str) </
sample
>
<
p
>
It is not immediately obvious how to rewrite this regular expression
to avoid the problem. However, you can mitigate performance issues by limiting the length
to 1000 characters, which will always finish in a reasonable amount
of time.
</
p
>
<
sample
language
=
"
python
"
>
if len(str)
>
1000:
raise ValueError("Input too long")
match = re.search(r'^(\+|-)?(\d+|(\d*\.\d*))?(E|e)?([-+])?(\d+)?$', str) </
sample
>
</
example
>
<
include
src
=
"
ReDoSReferences.inc.qhelp
"
/>
</
qhelp
>
You can’t perform that action at this time.