Solve Me First FP

• HackerRank link: hackerrank.com/challenges/fp-solve-me-first
• Difficulty: Easy
• Solution added: Haskell, Fsharp

Solution

Haskell

main = do
    a <- readLn :: IO Int
    b <- readLn :: IO Int
    print (a + b)

Explanation

main = do

We first create a block of main program.

    a <- readLn :: IO Int
    b <- readLn :: IO Int

Then, we ask user input. Both a and b read Integer from the IO.

    print (a + b)

Last, we simply print the sum of a and b. Why we use print instead of putStrLn? Because it's a number. That's it!