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## RETURN THE 'EVEN' IF STRING IS EVEN OTHERWISE RETURN FIRST LETTER OF A STRING

# SLICER FUNCTION DEFINE

def slicer(mystring):

# FIND THE LENGTH OF MYSTRING VARIABLE

if len(mystring)%2 == 0:

# IF THE LENGTH OF MYSTRING IS EVEN IT RETURNS EVEN

return 'even'

else:

# OTHERWISE RETURNS THE FIRST LETTER OF THE STRING

return mystring[0]

names = ['adam','eve','sla','rock','rio']

# HERE WE PRINT WITH THE MAP AND IN LIST FORMAT

print(list(map(slicer,names)))

## HOW TO RUN

# python: example_lambda_map.py

# ['even', 'e', 's', 'even', 'r']