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"""

문제링크 : https://programmers.co.kr/learn/courses/30/lessons/67256?language=python3

입력예시

numbers

[1, 3, 4, 5, 8, 2, 1, 4, 5, 9, 5]

[7, 0, 8, 2, 8, 3, 1, 5, 7, 6, 2]

[1, 2, 3, 4, 5, 6, 7, 8, 9, 0]

hand

"right"

"left"

"right"

결과예시

result

"LRLLLRLLRRL"

"LRLLRRLLLRR"

"LLRLLRLLRL"

"""

def solution(numbers, hand):

answer = ''

# *, 0, # -> 10, 11, 12로 변환해서 계산

current_left = 10

current_right = 12

for index in range(len(numbers)):

if numbers[index] == 0:

numbers[index] = 11

for number in numbers:

# n % 3을 통해 어느 라인에 있는 숫자인지 확인

line = number % 3

# 왼손 라인 -> 현재 왼손 값 변경, answer에 L 추가

if line == 1:

current_left = number

answer += 'L'

# 오른손 라인 -> 현재 오른손 값 변경, answer에 R 추가

if line == 0:

current_right = number

answer += 'R'

# 가운데 라인 -> 왼손, 오른손 거리 계산

if line == 2:

distance_left = int((abs(current_left - number) / 3) + (abs(current_left - number) % 3))

distance_right = int((abs(current_right - number) / 3) + (abs(current_right - number) % 3))

# 가까운 손에 현재 누른 번호값으로 변경, answer L or R 추가

if distance_left > distance_right:

current_right = number

answer += 'R'

elif distance_left < distance_right:

current_left = number

answer += 'L'

# 거리가 같다면 hand을 확인하여 그 손에 현재 누른 번호값 변경, answer L or R 추가

else:

if hand == "right":

current_right = number

answer += 'R'

if hand == "left":

current_left = number

answer += 'L'

return answer