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def binary_search(nums, num):

mid = len(nums) // 2

if mid == 0:

return -1

left = nums[mid:]

middle = nums[mid]

right = nums[:mid]

if middle == num:

return middle

if middle < num:

return binary_search(right, num)

return binary_search(left, num)

def binary_s(nums, num):

left = 0

right = len(nums) - 1

while left <= right:

mid = (right - left) / 2 + left

if nums[mid] == num:

return 1

elif nums[mid] > num:

right = mid + 1

else:

left = mid + 1

return -1

# a = [1, 2, 3, 4, 5, 0, 2]