private T t;

private U u;

private V v;

public Ternary(T t, U u, V v) {

this.t = t;

this.u = u;

this.v = v;

}

public T first() {

return t;

}

public void first(T t) {

this.t = t;

}

public U second() {

return u;

}

public void second(U u) {

this.u = u;

}

public V third() {

return v;

}

public void third(V v) {

this.v = v;

}

@Override

// Note: This means any two pairs with null for both values will match each

// other but what can I do? This is due to stupid type erasure.

public int hashCode() {

return (t != null ? t.hashCode() : 0) | (u != null ? u.hashCode() : 0) | (v != null ? v.hashCode() : 0);

}

@Override

public boolean equals(Object obj) {

if (!(obj instanceof Pair)) {

return false;

}

Ternary<?, ?, ?> that = (Ternary<?, ?, ?>)obj;

return (t != null ? t.equals(that.t) : that.t == null) && (u != null ? u.equals(that.u) : that.u == null) && (v != null ? v.equals(that.v): that.v == null);

}

@Override

public String toString() {

StringBuilder b = new StringBuilder("T[");

b.append(t != null ? t.toString() : "null");

b.append(":");

b.append(u != null ? u.toString() : "null");

b.append(":");

b.append(v != null ? v.toString() : "null");

b.append("]");

return b.toString();

}