T t;

U u;

protected Pair() {

}

public Pair(T t, U u) {

this.t = t;

this.u = u;

}

public T first() {

return t;

}

public U second() {

return u;

}

public U second(U value) {

u = value;

return u;

}

public T first(T value) {

t = value;

return t;

}

public void set(T t, U u) {

this.t = t;

this.u = u;

}

@Override

// Note: This means any two pairs with null for both values will match each

// other but what can I do? This is due to stupid type erasure.

public int hashCode() {

return (t != null ? t.hashCode() : 0) | (u != null ? u.hashCode() : 0);

}

@Override

public boolean equals(Object obj) {

if (!(obj instanceof Pair)) {

return false;

}

Pair<?, ?> that = (Pair<?, ?>)obj;

return (t != null ? t.equals(that.t) : that.t == null) && (u != null ? u.equals(that.u) : that.u == null);

}

@Override

public String toString() {

StringBuilder b = new StringBuilder("P[");

b.append((t != null) ? t.toString() : "null");

b.append(":");

b.append((u != null) ? u.toString() : "null");

b.append("]");

return b.toString();

}