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# https://en.wikipedia.org/wiki/Wheatstone_bridge

from __future__ import annotations

def wheatstone_solver(

resistance_1: float, resistance_2: float, resistance_3: float

) -> float:

"""

This function can calculate the unknown resistance in an wheatstone network,

given that the three other resistances in the network are known.

The formula to calculate the same is:

---------------

|Rx=(R2/R1)*R3|

---------------

Usage examples:

>>> wheatstone_solver(resistance_1=2, resistance_2=4, resistance_3=5)

10.0

>>> wheatstone_solver(resistance_1=356, resistance_2=234, resistance_3=976)

641.5280898876405

>>> wheatstone_solver(resistance_1=2, resistance_2=-1, resistance_3=2)

Traceback (most recent call last):

...

ValueError: All resistance values must be positive

>>> wheatstone_solver(resistance_1=0, resistance_2=0, resistance_3=2)

Traceback (most recent call last):

...

ValueError: All resistance values must be positive

"""

if resistance_1 <= 0 or resistance_2 <= 0 or resistance_3 <= 0:

raise ValueError("All resistance values must be positive")

else:

return float((resistance_2 / resistance_1) * resistance_3)

if __name__ == "__main__":

import doctest

doctest.testmod()

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