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| 1 | +package leetcode; |
| 2 | + |
| 3 | +import java.util.Stack; |
| 4 | + |
| 5 | +public class DecodeString { |
| 6 | + |
| 7 | + public static void main(String[] args) { |
| 8 | + // TODO Auto-generated method stub |
| 9 | + /* |
| 10 | + * StringBuilder sb = new StringBuilder("abcd"); sb.reverse(); |
| 11 | + * System.out.println(sb.toString()); int num = 1; while(num-- > 0){ |
| 12 | + * sb.append(sb); } System.out.println(sb.toString()); |
| 13 | + */ |
| 14 | + |
| 15 | + String s = "2[abc]3[cd]ef"; |
| 16 | + String t = "100[leetcode]"; |
| 17 | + System.out.println(decodeString(s)); |
| 18 | + |
| 19 | + System.out.println(evl("(1+((2+3)*(4*5)))")); |
| 20 | + |
| 21 | + } |
| 22 | + |
| 23 | + /** |
| 24 | + * 双栈,一个栈装数字,一个栈装字符串 |
| 25 | + * @param s |
| 26 | + * @return |
| 27 | + */ |
| 28 | + public static String decodeString(String s) { |
| 29 | + Stack<StringBuilder> strStack = new Stack<>(); |
| 30 | + Stack<Integer> intStack = new Stack<>(); |
| 31 | + |
| 32 | + StringBuilder cur = new StringBuilder(""); |
| 33 | + int num = 0; |
| 34 | + for (int i = 0; i < s.length(); i++) { |
| 35 | + char c = s.charAt(i); |
| 36 | + if (c == '[') { |
| 37 | + intStack.push(num); |
| 38 | + strStack.push(cur); |
| 39 | + cur = new StringBuilder(""); |
| 40 | + num = 0; |
| 41 | + } else if (c == ']') { |
| 42 | + StringBuilder temp = cur; |
| 43 | + cur = strStack.pop(); |
| 44 | + for (num = intStack.pop(); num > 0; --num){ |
| 45 | + cur.append(temp); |
| 46 | + } |
| 47 | + } else if (Character.isDigit(c)) { |
| 48 | + num = num * 10 + c - '0'; |
| 49 | + } else { |
| 50 | + cur.append(c); |
| 51 | + } |
| 52 | + } |
| 53 | + |
| 54 | + return cur.toString(); |
| 55 | + } |
| 56 | + |
| 57 | + /** |
| 58 | + * 同类体型,具体参见<算法4> |
| 59 | + * Dijkstra的双栈算术表达式 |
| 60 | + * @param str |
| 61 | + * @return |
| 62 | + */ |
| 63 | + public static Double evl(String str){ |
| 64 | + Stack<Double> vals = new Stack<Double>(); |
| 65 | + Stack<Character> op = new Stack<Character>(); |
| 66 | + char[] ch = str.toCharArray(); |
| 67 | + for(int i = 0;i < ch.length;i++){ |
| 68 | + if(ch[i] == '+') op.push(ch[i]); |
| 69 | + else if(ch[i] == '-') op.push(ch[i]); |
| 70 | + else if(ch[i] == '*') op.push(ch[i]); |
| 71 | + else if(ch[i] == '/') op.push(ch[i]); |
| 72 | + else if(ch[i] == '('); |
| 73 | + else if(ch[i] == ')'){ |
| 74 | + char o = op.pop(); |
| 75 | + Double val = vals.pop(); |
| 76 | + if(o == '+') val = val + vals.pop(); |
| 77 | + else if(o == '-') val = vals.pop() - val; |
| 78 | + else if(o == '*') val = vals.pop() * val; |
| 79 | + else if(o == '/') val = vals.pop() / val; |
| 80 | + vals.push(val); |
| 81 | + }else{ |
| 82 | + vals.push(Double.parseDouble(Character.toString(ch[i]))); |
| 83 | + } |
| 84 | + } |
| 85 | + return vals.pop(); |
| 86 | + } |
| 87 | + |
| 88 | +} |
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