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_posts/enchanted-forest/2013-03-17-horton.coffee.md

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_site/assets/images/hortonjr.jpg

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_site/atom.xml

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<title>raganwald.com</title>
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<link href="http://raganwald.com/"/>
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<link type="application/atom+xml" rel="self" href="http://raganwald.com/atom.xml"/>
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<updated>2013-03-17T19:11:42-04:00</updated>
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<updated>2013-03-17T19:14:33-04:00</updated>
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<id>http://raganwald.com/</id>
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<name>Reginald Braithwaite</name>
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&lt;h3 id=&quot;libert-galit-et-fraternit&quot;&gt;liberté, égalité, et fraternité&lt;/h3&gt;
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&lt;p&gt;“First,” said Horton, “What happens if we are given two birds that are part of a proper flock, but the first stands against the second &lt;em&gt;and&lt;/em&gt; the second bird stands against the first?”&lt;/p&gt;
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&lt;p&gt;“First,” said Horton, “What happens if we are given two birds that are part of a proper flock, but the first stands fast against the second &lt;em&gt;and&lt;/em&gt; the second bird stands fast against the first?”&lt;/p&gt;
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&lt;p&gt;Maude looked confused.&lt;/p&gt;
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&lt;p&gt;“Yes,” said Horton, “This is impossible unless they are the same bird or either of them is confused. A bird does not back down from itself! So we say that two birds are equal if they both stand against each other and neither is confused.”&lt;/p&gt;
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&lt;blockquote&gt;
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&lt;p&gt;Two birds are equal if they both stand against each other and neither is confused.&lt;/p&gt;
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&lt;p&gt;Two birds are equal if they both stand fast against each other and neither is confused.&lt;/p&gt;
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&lt;/blockquote&gt;
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&lt;pre&gt;&lt;code&gt;FlockingBird::equals = (otherBird) -&amp;gt;

_site/enchanted-forest/horton.html

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<h3 id="libert-galit-et-fraternit">liberté, égalité, et fraternité</h3>
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<p>“First,” said Horton, “What happens if we are given two birds that are part of a proper flock, but the first stands against the second <em>and</em> the second bird stands against the first?”</p>
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<p>“First,” said Horton, “What happens if we are given two birds that are part of a proper flock, but the first stands fast against the second <em>and</em> the second bird stands fast against the first?”</p>
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<p>Maude looked confused.</p>
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<p>“Yes,” said Horton, “This is impossible unless they are the same bird or either of them is confused. A bird does not back down from itself! So we say that two birds are equal if they both stand against each other and neither is confused.”</p>
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<blockquote>
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<p>Two birds are equal if they both stand against each other and neither is confused.</p>
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<p>Two birds are equal if they both stand fast against each other and neither is confused.</p>
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</blockquote>
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<pre><code>FlockingBird::equals = (otherBird) -&gt;

_site/rss.xml

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assets/images/hortonjr.jpg

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