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Integer_to_English_Words.py

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# LeetCode Problem Link - https://leetcode.com/problems/integer-to-english-words/

class Solution(object):

def numberToWords(self, num):

"""

:type num: int

:rtype: str

"""

def decode(triple_str):

final_list = []

numbers = { "1": "One",

"2": "Two",

"3": "Three",

"4": "Four",

"5": "Five",

"6": "Six",

"7": "Seven",

"8": "Eight",

"9": "Nine",

"10": "Ten",

"11": "Eleven",

"12": "Twelve",

"13": "Thirteen",

"14": "Fourteen",

"15": "Fifteen",

"16": "Sixteen",

"17": "Seventeen",

"18": "Eighteen",

"19": "Nineteen"}

tens = { "2": "Twenty",

"3": "Thirty",

"4": "Forty",

"5": "Fifty",

"6": "Sixty",

"7": "Seventy",

"8": "Eighty",

"9": "Ninety"}

if int(triple_str[0]) != 0:

final_list.append("{} Hundred".format(numbers[triple_str[0]]))

if int(triple_str[1]) == 1:

final_list.append("{}".format(numbers[triple_str[1:3]]))

else:

if int(triple_str[1]) != 0:

final_list.append("{}".format(tens[triple_str[1]]))

if int(triple_str[2]) != 0:

final_list.append("{}".format(numbers[triple_str[2]]))

return final_list

num_str = "{:0>12}".format(str(num))

num_list = []

final_num = ""

digit_dict = { 0: "Billion",

3: "Million",

6: "Thousand"}

for x in range(0, 12, 3):

the_triple = num_str[x:x+3]

if the_triple == "000":

continue

else:

num_list.extend(decode(the_triple))

if x == 9: break

num_list.append(digit_dict[x])

final_num = " ".join(num_list)

if final_num == "":

final_num = "Zero"

return final_num