Message 367580 - Python tracker

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Content 
The following code works on Python 3.8, but fails with SyntaxError on Python 3.9.0a6 with the old and the new parser (see bpo-40431):

    clear = "NORMAL"
    print(dict(state=clear, bg="#d00" if clear else"#fca"))

Well, the code looks like a typo error... but it worked previously. Not sure if we should keep the SyntaxError or not. Fixing the code is trivial: see PR 19777 attached to bpo-40431; replace >else"#fca"< with >else "#fca"<.