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Created on 2009-01-16 06:29 by kvutza, last changed 2022-04-11 14:56 by admin. This issue is now closed.
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| msg79934 - (view) | Author: Martin Saturka (kvutza) | Date: 2009-01-16 06:29 | |
Directory selection from Tkinter part of Python 3.0, i.e. "askdirectory" function from tkinter.filedialog does not work. It works for 2.x Python, other Tkinter functions (askopenfilename, asksaveasfilename) work well at both 2.x and 3.0 versions. |
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| msg79935 - (view) | Author: Martin v. Löwis (loewis) *  |
Date: 2009-01-16 06:41 | |
Please be more explicit: what does "not work" mean? What do you do, what happens, what do you expect to happen instead? |
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| msg79936 - (view) | Author: Martin Saturka (kvutza) | Date: 2009-01-16 06:56 | |
When I do in Python 2.x (e.g. 2.6) next: ---------------------------- import Tkinter as T import tkFileDialog as F t = T.Tk() dn = F.askdirectory() ---------------------------- It pop-ups the dialog, it is OK. Analogical case for Python 3.0 does not work, at least on my Linux box: ---------------------------- import tkinter as T import tkinter.filedialog as F t = T.Tk() dn = F.askdirectory() ---------------------------- It just writes an error message below: ---------------------------- Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/usr/local/lib/python3.0/tkinter/filedialog.py", line 430, in askdirectory return Directory(**options).show() File "/usr/local/lib/python3.0/tkinter/dialog.py", line 20, in __init__ cnf['title'], cnf['text'], KeyError: 'title' ---------------------------- When I had tried to put there all the parameters it was asking for, it just put some nonsense window. |
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| msg79937 - (view) | Author: Martin v. Löwis (loewis) * |
Date: 2009-01-16 07:05 | |
Ah. That's a duplicate of issue 4406. |
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